Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.1 Composite Functions - 5.1 Assess Your Understanding - Page 255: 62

Answer

$40000\pi t$

Work Step by Step

We know that $A_{\text{circle}}=r^2\pi$ and $r(t)=200\sqrt t.$ Therefore $A(r(t))=\pi (200\sqrt t)^2=40000\pi t$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.