Answer
$f(x)=\sqrt x$ and $g(x)=x^2+1$
Work Step by Step
If $f(x)=\sqrt x$ and $g(x)=x^2+1$ then $(f\circ g)(x)=f(g(x))=f(x^2+1)=\sqrt{(x^2+1)}=H(x).$
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