Answer
$(f\circ g)(x)=11.$
$(g\circ f)(x)=2$
Work Step by Step
$(f\circ g)(x)=f(g(x))=f(2)=(2)2^3-(3)2^2+4(2)-1=16-12+8-1=11.$
$(g\circ f)(x)=g(f(x))=g(2x^3-3x^2+4x-1)=2$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.1 Composite Functions - 5.1 Assess Your Understanding - Page 255: 53
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