Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.1 Composite Functions - 5.1 Assess Your Understanding - Page 255: 53


$(f\circ g)(x)=11.$ $(g\circ f)(x)=2$

Work Step by Step

$(f\circ g)(x)=f(g(x))=f(2)=(2)2^3-(3)2^2+4(2)-1=16-12+8-1=11.$ $(g\circ f)(x)=g(f(x))=g(2x^3-3x^2+4x-1)=2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.