## Precalculus (10th Edition)

We are given the functions: $f(x)=4x$ $g(x)=\dfrac{1}{4}x$ Determine $f\circ g$: $(f\circ g)(x)=f(g(x))=f\left(\dfrac{1}{4}x\right)=4\cdot\dfrac{1}{4}x=x$ Determine $g\circ f$: $(g\circ f)(x)=g(f(x))=g\left(4x\right)=\dfrac{1}{4}\cdot 4x=x$ We got: $(f\circ g)(x)=(g\circ f)(x)=x$