Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.1 Composite Functions - 5.1 Assess Your Understanding - Page 255: 52


$f(x)=|x|$ and $g(x)=2x^2+3$

Work Step by Step

If $f(x)=|x|$ and $g(x)=2x^2+3$ then $(f\circ g)(x)=f(g(x))=f(2x^2+3)=|2x^2+3|=H(x).$
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