Answer
$f(x)=|x|$ and $g(x)=2x^2+3$
Work Step by Step
If $f(x)=|x|$ and $g(x)=2x^2+3$ then $(f\circ g)(x)=f(g(x))=f(2x^2+3)=|2x^2+3|=H(x).$
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