Answer
$\begin{bmatrix}
1&1\\
2&3
\end{bmatrix}$
Work Step by Step
Using the formula,
$A^{-1} = \frac{1}{|A|}\times{Adj(A)}$
$where, A = \begin{bmatrix} 3&-1\\-2&1\end{bmatrix}$
$Adj(A) = \begin{bmatrix}d&-b\\-c&a\end{bmatrix}, if A = \begin{bmatrix}a&b\\c&d\end{bmatrix}$
$\implies A^{-1} = \frac{1}{(1)(3)-(-1)(-2)}\times\begin{bmatrix}1&1\\2&3\end{bmatrix}$
$= 1\times\begin{bmatrix}1&1\\2&3\end{bmatrix} = \begin{bmatrix}1&1\\2&3\end{bmatrix}$
