Answer
$\begin{bmatrix}
28 & -9\\
4 & 23
\end{bmatrix}$
Work Step by Step
$\begin{bmatrix}
0&3&-5\\
1&2&6
\end{bmatrix}\times\begin{bmatrix}
4&1\\
6&2\\
-2&3
\end{bmatrix}:$
Let M be the resultant matrix.
$\implies M_{1,1} = (0)(4)+(3)(6)+(-5)(-2) = 28$
$\implies M_{1,2} = (0)(1)+(3)(2)+(-5)(3) = -9$
$\implies M_{2,1} = (1)(4)+(2)(6)+(6)(-2) = 4$
$\implies M_{2,2} = (1)(1)+(2)(2)+(6)(3) = 23$
$\therefore M = \begin{bmatrix}
28 & -9\\
4 & 23
\end{bmatrix}$
