Answer
$\begin{bmatrix}
22&6\\
14&-2
\end{bmatrix}$
Work Step by Step
$\begin{bmatrix}
4&1&0\\
-2&3&-2
\end{bmatrix}\times\begin{bmatrix}
4&1\\
6&2\\
-2&3
\end{bmatrix}:$
Let the resultant be matrix M.
$\implies M_{1,1} = (4)(4)+(1)(6)+(0)(-2) = 22$
$\implies M_{1,2} = (4)(1)+(1)(2)+(0)(3) = 6$
$\implies M_{2,1} = (-2)(4)+(3)(6)+(-2)(-2) = 14$
$\implies M_{2,2} = (-2)(1)+(3)(2)+(-2)(3) = -2$
$\therefore M = \begin{bmatrix}
22&6\\
14&-2
\end{bmatrix}$
