Answer
$\begin{bmatrix}
1&14&-14\\
2&22&-18\\
3&0&28
\end{bmatrix}$
Work Step by Step
$\begin{bmatrix}
4&1\\
6&2\\
-2&3
\end{bmatrix}\times\begin{bmatrix}
0&3&-5\\
1&2&6
\end{bmatrix}:$
Let the resultant be matrix M.
$\implies M_{1,1} = (4)(0)+(1)(1) = 1$
$\implies M_{1,2} = (4)(3)+(1)(2) = 14$
$\implies M_{1,3} = (4)(-5)+(1)(6) = -14$
$\implies M_{2,1} = (6)(0)+(2)(1) = 2$
$\implies M_{2,2} = (6)(3)+(2)(2) = 22$
$\implies M_{2,3} = (6)(-5)+(2)(6) = -18$
$\implies M_{3,1} = (-2)(0)+(3)(1) = 3$
$\implies M_{3,2} = (-2)(3)+(3)(2) = 0$
$\implies M_{3,3} = (-2)(-5)+(3)(6) = 28$
$\therefore M = \begin{bmatrix}
1&14&-14\\
2&22&-18\\
3&0&28
\end{bmatrix}$
