Answer
$\begin{bmatrix}
-2&4&2&8\\
2&1&4&6
\end{bmatrix}$
Work Step by Step
To find: $\begin{bmatrix}
2&-2\\
1&0\end{bmatrix}\begin{bmatrix}2&1&4&6\\3&-1&3&2\end{bmatrix}$
Let the resultant be matrix M.
$\implies M_{1,1} = (2)(2)+(-2)(3) = -2$
$\implies M_{1,2} = (2)(1)+(-2)(-1) = 4$
$\implies M_{1,3} = (2)(4)+(-2)(3) = 2$
$\implies M_{1,4} = (2)(6)+(-2)(2) = 8$
$\implies M_{2,1} = (1)(2)+(0)(3) = 2$
$\implies M_{2,2} = (1)(1)+(0)(-1) = 1$
$\implies M_{2,3} = (1)(4)+(0)(3) = 4$
$\implies M_{2,4} = (1)(6)+(0)(2) = 6$
$\therefore M = \begin{bmatrix}
-2&4&2&8\\
2&1&4&6
\end{bmatrix}$
