Answer
$\begin{bmatrix}6&14&-14\\2&27&-18\\3&0&33\end{bmatrix}$
Work Step by Step
Refer to sum $\#17$ for determination of $CA$.
$\implies I_{3} = \begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}\implies5I_{3} = \begin{bmatrix}5&0&0\\0&5&0\\0&0&5\end{bmatrix}$
$\implies \begin{bmatrix}1&14&-14\\2&22&-18\\3&0&28\end{bmatrix}+\begin{bmatrix}5&0&0\\0&5&0\\0&0&5\end{bmatrix} = CA+5I_{3}$
We add matrices by adding their respective individual elements.
$\therefore CA+5I_{3} = \begin{bmatrix}1+5&14&-14\\2&22+5&-18\\3&0&28+5\end{bmatrix}=\begin{bmatrix}6&14&-14\\2&27&-18\\3&0&33\end{bmatrix}$
