Answer
$\begin{bmatrix}
-22&29&8&-1\\
-10&17&6&-1
\end{bmatrix}$
Work Step by Step
To find: $\begin{bmatrix}4&1\\2&1\end{bmatrix}\begin{bmatrix}-6&6&1&0\\2&5&4&-1\end{bmatrix}$
Let the resultant matrix be matrix M.
$\implies M_{1,1} = (4)(-6)+(1)(2)=-22$
$\implies M_{1,2} = (4)(6)+(1)(5) = 29$
$\implies M_{1,3} = (4)(1)+(1)(4) = 8$
$\implies M_{1,4} = (4)(0)+(1)(-1) = -1$
$\implies M_{2,1} = (2)(-6)+(1)(2) = -10$
$\implies M_{2,2} = (2)(6)+(1)(5) = 17$
$\implies M_{2,3} = (2)(1)+(1)(4) = 6$
$\implies M_{2,4} = (2)(0)+(1)(-1) = -1$
$\therefore M = \begin{bmatrix}
-22&29&8&-1\\
-10&17&6&-1
\end{bmatrix}$
