Answer
$\begin{bmatrix}
9&2\\
34&13\\
47&20
\end{bmatrix}$
Work Step by Step
To Find: $\begin{bmatrix}
1&0&1\\
2&4&1\\
3&6&1
\end{bmatrix}\begin{bmatrix}
1&3\\
6&2\\
8&-1
\end{bmatrix}$
Let the resultant be Matrix M.
$\implies M{1,1} = (1)(1)+(0)(6)+(1)(8) = 9$
$\implies M_{1,2} = (1)(3)+(0)(2)+(1)(-1) = 2$
$\implies M_{2,1} = (2)(1)+(4)(6)+(1)(8) = 34$
$\implies M_{2,2} = (2)(3)+(4)(2)+(1)(-1) = 13$
$\implies M_{3,1} = (3)(1)+(6)(6)+(1)(8) = 47$
$\implies M_{3,2} = (3)(3)+(6)(2)+(1)(-1) = 20$
$\therefore M = \begin{bmatrix}
9&2\\
34&13\\
47&20
\end{bmatrix}$
