Answer
$\begin{bmatrix}
-1&2&-1\\
0&-12&3\\
15&30&0
\end{bmatrix}$
Work Step by Step
To find: $\begin{bmatrix}1&-1\\-3&2\\0&5\end{bmatrix}\begin{bmatrix}2&8&-1\\3&6&0\end{bmatrix}$
Let the resultant be matrix $M$.
$\implies M_{1,1} = (1)(2)+(-1)(3) = -1$
$\implies M_{1,2} = (1)(8)+(-1)(6) = 2$
$\implies M_{1,3} = (1)(-1)+(-1)(0) = -1$
$\implies M_{2,1} = (-3)(2)+(2)(3) = 0$
$\implies M_{2,2} = (-3)(8)+(2)(6) = -12$
$\implies M_{2,3} = (-3)(-1)+(2)(0) = 3$
$\implies M_{3,1} = (0)(2)+(5)(30 = 15$
$\implies M_{3,2} = (0)(8)+(5)(6) = 30$
$\implies M_{3,3} = (0)(-1)+(5)(0) = 0$
$\therefore M = \begin{bmatrix}
-1&2&-1\\
0&-12&3\\
15&30&0
\end{bmatrix}$
