Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 34

Answer

$-\frac{21}{36}$

Work Step by Step

When $x=-\frac{1}{3}$ and $z=\frac{5}{6}$: $x^{2}-z^{2}$ $=(-\frac{1}{3})^{2}-(\frac{5}{6})^{2}$ $=[(-\frac{1}{3}\times(-\frac{1}{3})]-(\frac{5}{6}\times\frac{5}{6})$ $=(\frac{1}{3}\times\frac{1}{3})-\frac{25}{36}$ $=\frac{1}{9}-\frac{25}{36}$ $=\frac{4}{36}-\frac{25}{36}$ $=-\frac{21}{36}$
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