#### Answer

$\frac{16}{27}$

#### Work Step by Step

$(\frac{8}{9})^{2}\div(2-\frac{2}{3})$
$=(\frac{8}{9}\times\frac{8}{9})\div(\frac{6}{3}-\frac{2}{3})$
$=\frac{64}{81}\div\frac{4}{3}$
$=\frac{64}{81}\times\frac{3}{4}$
$=\frac{16}{27}\times\frac{1}{1}$
$=\frac{16}{27}$