Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 284: 20

Answer

$-6\frac{3}{4}$

Work Step by Step

$(-\frac{2}{3}-\frac{7}{3})\div\frac{4}{9}$ $=(-\frac{9}{3})\div\frac{4}{9}$ $=(-\frac{3}{1})\div\frac{4}{9}$ $=-(\frac{3}{1}\div\frac{4}{9})$ $=-(\frac{3}{1}\times\frac{9}{4})$ $=-\frac{27}{4}$ $=-6\frac{3}{4}$
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