Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 284: 12

Answer

$\frac{5}{9}$

Work Step by Step

$\frac{1}{2}+\frac{1}{6}\times\frac{1}{3}$ $=\frac{1}{2}+(\frac{1}{6}\times\frac{1}{3})$ $=\frac{1}{2}+\frac{1}{18}$ $=\frac{9}{18}+\frac{1}{18}$ $=\frac{10}{18}$ $=\frac{5}{9}$
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