Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 27

Answer

$\frac{9}{64}$

Work Step by Step

$(\frac{3}{4}+\frac{1}{8})^{2}-(\frac{1}{2}+\frac{1}{8})$ $=(\frac{6}{8}+\frac{1}{8})^{2}-(\frac{4}{8}+\frac{1}{8})$ $=(\frac{7}{8})^{2}-\frac{5}{8}$ $=(\frac{7}{8}\times\frac{7}{8})-\frac{5}{8}$ $=\frac{49}{64}-\frac{5}{8}$ $=\frac{49}{64}-\frac{40}{64}$ $=\frac{9}{64}$
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