Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 284: 27



Work Step by Step

$(\frac{3}{4}+\frac{1}{8})^{2}-(\frac{1}{2}+\frac{1}{8})$ $=(\frac{6}{8}+\frac{1}{8})^{2}-(\frac{4}{8}+\frac{1}{8})$ $=(\frac{7}{8})^{2}-\frac{5}{8}$ $=(\frac{7}{8}\times\frac{7}{8})-\frac{5}{8}$ $=\frac{49}{64}-\frac{5}{8}$ $=\frac{49}{64}-\frac{40}{64}$ $=\frac{9}{64}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.