Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 284: 26



Work Step by Step

$(\frac{3}{2}-\frac{4}{3})^{3}$ $=(\frac{9}{6}-\frac{8}{6})^{3}$ $=(\frac{1}{6})^{3}$ $=(\frac{1}{6}\times\frac{1}{6}\times\frac{1}{6})$ $=(\frac{1}{36}\times\frac{1}{6})$ $=\frac{1}{216}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.