Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 26

Answer

$\frac{1}{216}$

Work Step by Step

$(\frac{3}{2}-\frac{4}{3})^{3}$ $=(\frac{9}{6}-\frac{8}{6})^{3}$ $=(\frac{1}{6})^{3}$ $=(\frac{1}{6}\times\frac{1}{6}\times\frac{1}{6})$ $=(\frac{1}{36}\times\frac{1}{6})$ $=\frac{1}{216}$
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