#### Answer

$2$

#### Work Step by Step

When $x=-\frac{1}{3}$ and $z=\frac{5}{6}$:
$2z-x$
$=(2\times\frac{5}{6})-(-\frac{1}{3})$
$=(\frac{2}{1}\times\frac{5}{6})+\frac{1}{3}$
$=(\frac{1}{1}\times\frac{5}{3})+\frac{1}{3}$
$=\frac{5}{3}+\frac{1}{3}$
$=\frac{6}{3}$
$=2$