Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 28

Answer

$\frac{43}{200}$

Work Step by Step

$(\frac{1}{6}+\frac{1}{3})^{3}+(\frac{2}{5}\times\frac{3}{4})^{2}$ $=(\frac{1}{6}+\frac{2}{6})^{3}+(\frac{1}{5}\times\frac{3}{2})^{2}$ $=(\frac{3}{6})^{3}+(\frac{3}{10})^{2}$ $=(\frac{1}{2})^{3}+(\frac{3}{10})^{2}$ $=(\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2})+(\frac{3}{10}\times\frac{3}{10})$ $=(\frac{1}{4}\times\frac{1}{2})+\frac{9}{100}$ $=\frac{1}{8}+\frac{9}{100}$ $=\frac{25}{200}+\frac{18}{200}$ $=\frac{43}{200}$
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