Answer
$3\frac{1}{2}$
Work Step by Step
$(\frac{3}{2})^{3}+(\frac{1}{2})^{3}$
$=\frac{3^{3}}{2^{3}}+\frac{1^{3}}{2^{3}}$
$=\frac{3\times3\times3}{2\times2\times2}+\frac{1\times1\times1}{2\times2\times2}$
$=\frac{9\times3}{4\times2}+\frac{1\times1}{4\times2}$
$=\frac{27}{8}+\frac{1}{8}$
$=\frac{28}{8}$
$=3\frac{4}{8}$
$=3\frac{1}{2}$
