Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises - Page 335: 77



Work Step by Step

Rationalize the denominator by multiplying $3$ to both the numerator and the denominator within the radical sign to obtain: $=\sqrt{\dfrac{2}{3} \cdot \dfrac{3}{3}} \\=\sqrt{\dfrac{6}{9}} \\=\sqrt{\dfrac{6}{3^2}} \\=\dfrac{\sqrt6}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.