Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises - Page 335: 76



Work Step by Step

Rationalize the denominator by multiplying $\sqrt5$ to both the numerator and the denominator to obtain: $=\dfrac{30}{\sqrt5} \cdot \dfrac{\sqrt5}{\sqrt5} \\=\dfrac{30\sqrt5}{5} \\=6\sqrt5$
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