Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises - Page 335: 61


Chicken needed to serve \[15\]persons is \[11\frac{1}{4}\text{pounds}\].

Work Step by Step

When the number of persons was \[6\], then the amount of chicken required was \[4\frac{1}{2}\]pounds. Now, when the number of persons is \[15\], then the amount of chicken is, \[\left( \text{Amount of sugar needed currently} \right)=\frac{\left( \text{Number of persons currently} \right)}{\left( \text{Number of persons initially} \right)}\times \left( \text{Amount of sugar needed initially} \right)\] Put all the values to calculate the amount of sugar needed: Amount of sugar needed \[\begin{align} & =\left( \frac{15}{6} \right)\times \left( \frac{9}{2} \right)\text{pounds} \\ & =\frac{45}{4}\text{pounds} \\ & =11\frac{1}{4}\text{pounds} \end{align}\] Hence, chicken needed to serve \[15\]persons is \[11\frac{1}{4}\text{pounds}\].
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.