## Thinking Mathematically (6th Edition)

$\dfrac{35}{6}$
Convert each factor to an improper fraction to find: $=\dfrac{3(3)+1}{3} \cdot \dfrac{4(1)+3}{4} \\=\dfrac{10}{3} \cdot \dfrac{7}{4}$ Factor each numerator and denominator, when needed, and then cancel common factors to find: $\\\require{cancel}=\dfrac{2(5)}{3} \cdot \dfrac{7}{2(2)} \\=\dfrac{\cancel{2}(5)}{3} \cdot \dfrac{7}{\cancel{2}(2)} \\=\dfrac{5}{3} \cdot \dfrac{7}{2}$ Multiply the numerators together and the denominators together to find: $=\dfrac{5(7)}{3(2)} \\=\dfrac{35}{6}$