Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises - Page 335: 64

Answer

$\sqrt{72}=6\sqrt{2}$

Work Step by Step

Factor the radicand so that one of the factors is a perfect square: $=\sqrt{36(2)} \\=\sqrt{6^2(2)}$ Remove the squared symbol from the perfect square and bring it outside the square root symbol. $=6\sqrt{2}$
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