## Thinking Mathematically (6th Edition)

$3$
RECALL: For positive real numbers $a$ and $b$, $\dfrac{\sqrt{a}}{\sqrt{b}} = \sqrt{\dfrac{a}{b}}$ Use the rule above to obtain: $=\sqrt{\dfrac{27}{3}} \\=\sqrt{9} \\=\sqrt{3^2} \\=3$