Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises - Page 335: 50

Answer

$\dfrac{8}{3}$

Work Step by Step

RECALL: $\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \cdot \frac{d}{c}$ Use the rule above to find: $=\frac{4}{5} \cdot \frac{10}{3}$ Cancel the common factor 5 to find: $=\frac{4}{1} \cdot \frac{2}{3}$ Multiply the numerators together and the denominators together to find: $=\dfrac{4(2)}{1(3)} \\=\dfrac{8}{3}$
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