Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - 4.2 Number Bases in Positional Systems - Exercise Set 4.2 - Page 226: 9

Answer

$455$

Work Step by Step

The expanded form of $2035_{\text{six}}$ is: $=(2 \times 6^3) + (0\times 6^2)+(3 \times 6^1) + (5 \times 1) \\=(2\times 216) + 0 + (3 \times 6)+5 \\=4322 +18 +5 \\=455$
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