Answer
$101_{\text{two}}$
Work Step by Step
The place values of base two are: $,,,, 2^3, 2^2, 2^1, 1$.
The place value that are less then $5$ are $2^2, 2^1$ and $1$
Divide $5$ by $2^2$ or $4$ to obtain:
$5 \div 4 = 1$ remainder $1$
Divide the remainder $1$ by $2^1$ or $2$ to obtain:
$1 \div 2 = 0$ remainder $1$
Divide $1$ by $1$ to obtain $1 \div 1= 1$
Thus,
1$5=(2 \times 2^2) + (0 \times 2) + (1 \times 1)
\\5=101_{\text{two}}$
