Answer
The binary code for $p$ is:
$1110000$
Work Step by Step
The essay states that the lowercase letter $p$ is assigned the number $112$.
To find the binary representation for this, use division.
The place values in base two are $..., 2^7, 2^6, 2^5, 2^4, 2^3, 2^2, 2^1, 1$
The place values that are less than or equal to $112$ are $2^6, 2^5, 2^4, 2^3, 2^2, 2^1$ and $1$.
Divide $112$ by $2^6$ or $64$:
$112 \div 64 = 1$ remainder $48$
Divide $48$ by $2^5$ or $32$
$48 \div 32 = 1$ remainder $16$
Divide $16$ by $2^4$ or $16$:
$16 \div 16 = 1$ remainder $0$
Divide $0$ by $2^3$ or $8$:
$0 \div 8 = 0$ remainder $0$
Divide $0$ by $2^2$ or $4$:
$0 \div 4=0$ remainder $0$
Divide $0$ by $2^1$ or $2$:
$0 \div 2 = 0$ remainder $0$
Divide $0$ by $1$:
$0 \div 1 = 0$
Thus,
$112 = (1 \times 2^6) + (1 \times 2^5) + (1 \times 2^4)+(0 \times 2^3)+(0\times 2^2) + (0 \times 2^1)+(0 \times 1)
\\112=1110000_{\text{two}}$
