Answer
$2502_{\text{eight}}$
Work Step by Step
The place values of base eight are: $...,8^4, 8^3, 8^2, 8^1, 1$.
The place values that are less than or equal to $1346$ are $8^3, 8^2$, $8^1$, and $1$
Divide $1346$ by $8^3$ or $512$ to obtain:
$1346 \div 512 = 2$ remainder $322$
Divide $322$ by $8^2$ or $64$ to obtain:
$322 \div 64 = 5$ remainder $2$
Divide the remainder $2$ by $8^1$ or $8$ to obtain:
$2 \div 8 = 0$ remainder $2$
Divide the remainder $2$ by $1$ to obtain:
$2\div 1 = 2$ remainder $0$
Thus,
$1346=(2 \times 8^3) + (5 \times 8^2) + (0 \times 8^1) + (2 \times 1)
\\1346=2502_{\text{eight}}$
