Answer
The capital letters A through Z are assigned 65 through 90.
The lower-case letters a through z are assigned 97 through 122.
Accordingly,
\[M=77\],\[o=111\]and \[m=109\]
Convert each base ten number to binary by repeated division by 2 with the remainder obtained or mentally convert by forming groups of place-value.
\[\begin{align}
& 77=\left( 1\times {{2}^{6}} \right)+\left( 0\times {{2}^{5}} \right)+\left( 0\times {{2}^{4}} \right)+\left( 1\times {{2}^{3}} \right)+\left( 1\times {{2}^{2}} \right)+\left( 0\times {{2}^{1}} \right)+\left( 1\times {{2}^{0}} \right) \\
& ={{1001101}_{\operatorname{two}}}
\end{align}\]
\[\begin{align}
& 111=\left( 1\times {{2}^{6}} \right)+\left( 1\times {{2}^{5}} \right)+\left( 0\times {{2}^{4}} \right)+\left( 1\times {{2}^{3}} \right)+\left( 1\times {{2}^{2}} \right)+\left( 1\times {{2}^{1}} \right)+\left( 1\times {{2}^{0}} \right) \\
& ={{1101111}_{\operatorname{two}}}
\end{align}\]
\[\begin{align}
& 109=\left( 1\times {{2}^{6}} \right)+\left( 1\times {{2}^{5}} \right)+\left( 0\times {{2}^{4}} \right)+\left( 1\times {{2}^{3}} \right)+\left( 1\times {{2}^{2}} \right)+\left( 0\times {{2}^{1}} \right)+\left( 1\times {{2}^{0}} \right) \\
& ={{1101101}_{\operatorname{two}}}
\end{align}\]
The binary sequence is \[\underline{1001101}\underline{1101111}\underline{1101101}\].
Binary representation for word Mom is \[100110111011111101101\]
