Answer
$44,261$
Work Step by Step
RECALL:
in the hexadecimal system. $A= 10$, $C=12$, and $E=14$.
Thus, the expanded form of $ACE5_{\text{sixteen}}$ is:
$=(10 \times 16^3) + (12 \times 16^2)+(14 \times 16^1) + (5 \times 1)
\\=(10 \times 4096) + (12 \times 256) + (14 \times 16) + 5
\\=40,960+3,072 + 224+5
\\=44,261$
