Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - 4.2 Number Bases in Positional Systems - Exercise Set 4.2: 8

Answer

$13$

Work Step by Step

The expanded form of $1101_{\text{two}}$ is: $=(1 \times 2^3) + (1\times 2^2)+(0 \times 2^1) + (1 \times 1) \\=(1\times 8) + (1 \times 4)+0 + 1 \\=8 +4 + 1 \\=13$
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