Answer
$41_{\text{six}}$
Work Step by Step
The place values of base six are: $,,,, 6^3, 6^2, 6^1, 1$.
The place value that are less than $25$ are $6^1$, and $1$
Divide $25$ by $6^1$ or $6$ to obtain:
$25 \div 6 = 4$ remainder $1$
Divide the remainder $1$ by $1$ to obtain:
$1 \div 1 = 1$ remainder $0$
Thus,
$25=(4 \times 6^1) + (1 \times 1)
\\25=41_{\text{six}}$
