Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - 4.2 Number Bases in Positional Systems - Exercise Set 4.2: 29

Answer

$31_{\text{four}}$

Work Step by Step

The place values of base four are: $,,,, 4^3, 4^2, 4^1, 1$. The place value that are less than or equal to $13$ are $4^1$ and $1$ Divide $13$ by $4^1$ or $4$ to obtain: $13 \div 4 = 3$ remainder $1$ Divide the remainder $1$ by $1$ to obtain: $1 \div 1 = 1$ remainder $0$ Thus, $13=(3 \times 4^1) + (1 \times 1) \\13=31_{\text{four}}$
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