University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 320: 9


$2\sqrt 3$

Work Step by Step

$\int_{0}^{\pi/3} (2sec^2x)dx=2\cdot\int_{0}^{\pi/3} (sec^2x)dx=2\cdot[tanx]_{0}^{\pi/3}=2\cdot[tan\frac{\pi}{3}]-2\cdot[tan0]=2\sqrt 3-0=2\sqrt 3$
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