Answer
$2\sqrt 3$
Work Step by Step
$\int_{0}^{\pi/3} (2sec^2x)dx=2\cdot\int_{0}^{\pi/3} (sec^2x)dx=2\cdot[tanx]_{0}^{\pi/3}=2\cdot[tan\frac{\pi}{3}]-2\cdot[tan0]=2\sqrt 3-0=2\sqrt 3$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 320: 9
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