Answer
$\frac{5}{2}$
Work Step by Step
$\int_{1}^{32} (x^{-6/5})dx=[\frac{x^{-6/5+1}}{-6/5+1}]_{1}^{32}=[\frac{x^{-1/5}}{-1/5}]_{1}^{32}=[\frac{32^{-1/5}}{-1/5}]-[\frac{1^{-1/5}}{-1/5}]=\frac{-5}{2}+5=\frac{5}{2}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 320: 8
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
