Answer
$0$
Work Step by Step
$\int_{-1}^{1} x^{299}dx=[\frac{x^{300}}{300}]_{-1}^{1}=[\frac{1^{300}}{300}]-[\frac{(-1)^{300}}{300}]=[\frac{1}{300}]-[\frac{1}{300}]=0$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 320: 4
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