University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises: 4

Answer

$0$

Work Step by Step

$\int_{-1}^{1} x^{299}dx=[\frac{x^{300}}{300}]_{-1}^{1}=[\frac{1^{300}}{300}]-[\frac{(-1)^{300}}{300}]=[\frac{1}{300}]-[\frac{1}{300}]=0$
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