University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 320: 3

Answer

$\frac{124}{125}$

Work Step by Step

\begin{aligned}\int_{-2}^{2} \frac{3}{(x+3)^{4}} d x&= \int_{-2}^{2} 3(x+3)^{-4} d x\\ &= -\frac{3}{3}(x+3)^{-3}\bigg|_{-2}^{2}\\ &= -\left( \frac{1}{5^3}-1\right)\\ &=-\frac{1-125}{125}\\ &= \frac{124}{125} \end{aligned}
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