University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 320: 11

Answer

$0$

Work Step by Step

$\int_{\pi/4}^{3\pi/4} (csc\theta cot\theta) d\theta=[-csc\theta]_{\pi/4}^{3\pi/4}=[-csc\frac{3\pi}{4}]-[-csc\frac{\pi}{4}]=-\sqrt 2+\sqrt 2=0$
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