Answer
$\pi$
Work Step by Step
$\int_{0}^{\pi} (1+cosx)dx=[x+sin x]_{0}^{\pi}=[\pi+sin \pi]-[0+sin0]=
[\pi+0]-[0+0]=\pi$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.