Answer
$\frac{7}{3}$
Work Step by Step
$\int_{0}^{ln2} (e^{3x}) dx=[\frac{1}{3}\cdot e^{3x}]_{0}^{ln2}=[\frac{1}{3}\cdot e^{3\cdot ln2}]-[\frac{1}{3}\cdot e^{3\cdot 0}]=\frac{8}{3}-\frac{1}{3}=\frac{7}{3}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 320: 29
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
