Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 4

Answer

$0$

Work Step by Step

Substitute $1,2,3,4,5$ to $k$ and calculate the sum: $$\begin{align*} \displaystyle\Sigma_{k=1}^5 \sin k\pi &\\ &=\sin \pi+\sin 2\pi+\sin 3\pi+\sin 4\pi+\sin 5\pi \\ &=0+0+0+0+0\\ &=0. \end{align*}$$
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