Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 29


a)21 b)3500 c)2620

Work Step by Step

a)$\Sigma^7 _{k=1}$3=3(7)=21 b)$\Sigma^{500} _{k=1}$7=7(500)=3500 c)let $j=k-2$ $k=j+2$ if $k=3 =>j=1$ and if $ k=264 => j=262$ =a)$\Sigma^{264} _{k=3}$ 10 =a)$\Sigma^{262} _{j=1}$10=10(262)=2620
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