Answer
$5\Sigma_{k=1} (-1)^{k+1} \frac{1}{k}$
Work Step by Step
- Put k=1 to 5 into $(-1)^{k+1} \frac{1}{k}$ from which we get the
following Sigma Notation which is equal to 1-$\frac{1}{2}$+$\frac{1}{3}$+$\frac{1}{4}$+$\frac{1}{5}$
-- $5\Sigma_{k=1} (-1)^{k+1} \frac{1}{k}$=1-$\frac{1}{2}$+$\frac{1}{3}$-$\frac{1}{4}$+$\frac{1}{5}$
