Answer
$\frac{7}{6}$
Work Step by Step
3$\Sigma$k=1 writing this with put sigma notation
2$\Sigma$k=1$\frac{k-1}{k}$ =>$\frac{1-1}{1}$ => $\frac{2-1}{2}$
=>$\frac{3-1}{3}$ =>0+$\frac{1}{2}$+$\frac{2}{3}$=$\frac{7}{6}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 2
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